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A triangular wire frame (each side =2m) ...

A triangular wire frame (each side =2m) is placed in a region of time variant magnetic field `dB//dt = (sqrt3) T//s`. The magnetic field is perpendicular to the plane of the triangle and its centre coincides with the centre of triangle. The base of the triangle AB has a resistance `1(Omega)` while the other two sides have resistance `2(Omega)` each. The magnitude of potential difference between the points A and B will be

A

`0.4 V`

B

`0.6 V`

C

`1.2 V`

D

None

Text Solution

Verified by Experts

The correct Answer is:
B

`P.D` in the loop `= int vec(E).d vec(l) = (d phi)/(dt) = A(dB)/(dt)`
`i = (Delta V)/(R_(T))" " R_(T) = 5 Omega , V_(AB) = iR_(AB)`
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