Two coaxial circular loops of radius `0.5 m` and `5 xx 10^(-2)m` are separated by a distance `0.5 m` and carry currents `2 A` and `1 A` respectively. The force between the loops due to mutual induction is

Options

A. `2.09 xx 10^(-8) N`
B. `1.06 xx 10^(-6) N`
C. `4.18 xx 10^(-8) N`
D. `8.3 xx 10^(-5) N`

Answer

A

Explanation

`F = (mu_(0))/(4pi)(6M_(1)M_(2))/(d^(4))`
where `M_(1) = n_(1)i_(1)A_(1), M_(2) = n_(2)i_(2)A_(2)`