An inductance of `(200)/(pi) mH` a capacitance of `(10^(-3))/(pi)` and a resistance of `10 Omega` are connected in series with an `AC` source of `220 V, 50Hz`. The phase angle of the circuit is

Explanation

To find the phase angle \( \phi \) of the RLC circuit, we will follow these steps:

### Step 1: Identify the given values
- Inductance \( L = \frac{200}{\pi} \, \text{mH} = \frac{200 \times 10^{-3}}{\pi} \, \text{H} = \frac{0.2}{\pi} \, \text{H} \)
- Capacitance \( C = \frac{10^{-3}}{\pi} \, \text{F} \)
- Resistance \( R = 10 \, \Omega \)
- Frequency \( f = 50 \, \text{Hz} \)

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