Home
Class 12
PHYSICS
The r.m.s value of an a.c of 59 Hz is 10...

The r.m.s value of an a.c of `59 Hz` is `10 A`. The time taken by the alternating current in reaching from zero to maximum valuef and the peak value of current will be

A

`2 xx 10^(-2) "sec"` and `14.14 A`

B

`1 xx 10^(-2) "sec"` and `7.07 A`

C

`5 xx 10^(-3) "sec"` and `7.07 A`

D

`5 xx 10^(-3) "sec"` and `14.14 A`

Text Solution

Verified by Experts

The correct Answer is:
4
`i_(0) = sqrt(2) i_("rms")` , `T = (1)/(f), t = (T)/(4)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ALTERNATING CURRENT

    NARAYNA|Exercise LEVEL - II (C.W)|11 Videos

  • ALTERNATING CURRENT

    NARAYNA|Exercise LEVEL - III (C.W)|24 Videos

  • ALTERNATING CURRENT

    NARAYNA|Exercise Assertion & Reason|14 Videos

  • ATOMIC PHYSICS

    NARAYNA|Exercise LEVEL-II (H.W)|14 Videos

Similar Questions

Explore conceptually related problems

The r.m.s. value of an a.c. of 50Hz is 10A. The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be

The rms value of an AC of 50Hz is 20 amp. The time taken by an alternating current in reaching from zero to maximum value and the pack value of current will be

Knowledge Check

  • The rms value of an ac of 50Hz is 10A. The time taken be an alternating current in reaching from zero to maximum value and the peak value will be

    A
    `2xx10^(-2) s and 14.14 A`
    B
    `1xx10^(-2) s and 7.07 A`
    C
    `5xx10^(-3) s and 7.07 A`
    D
    `5xx10^(-3) s and 14.14 A`

  • The root-mean-square value of an alternating current of 50 Hz frequency is 10 ampere. The time taken by the alternating current in reaching from zero to maximum value and the peak value of current will be

    A
    `2 xx 10^(-2) sec and 14.14 amp`
    B
    `1xx 10^(-2) sec and 7.07 amp`
    C
    `5 xx 10^(-3) sec and 7.07 amp`
    D
    `5 xx 10^(-3)sec and 14.14 amp`

  • The time taken by an AC of 50 Hz in reaching from zero to its maximum value will be

    A
    `0.5 s`
    B
    `0.005 s`
    C
    `0.05 s`
    D
    `5 s`

    • Similar Questions

    Explore conceptually related problems

    The r.m.s. value of an ac of 50 Hz is 10 A. (1) The time taken by the alternating current in reaching from zero to maximum value is 5×10–3 sec (2) The time taken by the alternating current in reaching from zero to maximum value is 2×10–3 sec (3) The peak current is 14.14 A (4) The peak current is 7.07 A

    The time taken by an alternating current i=i_(0)sin(314t) in reaching from zero to its maximum value will be

    The r.m.s. value of an alternating current is

    The time required for a 50Hz alternating current to increase from zero to 70.7% of its peak value is-

    For an alternating current I = I_(0) cosomegat , what is the rms value and peak value of current-

    Home
    Profile