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A condenser of 10 mu F and an inductor o...

A condenser of `10 mu F` and an inductor of `1 H` are connected in series with an `A.C` source of frequency `50 Hz`. The impedance of the combination will be (take `pi^(2) = 10)`

A

zero

B

Inifinity

C

`44.7 Omega`

D

`5.67 Omega`

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The correct Answer is:
To find the impedance of a series combination of a capacitor and an inductor connected to an AC source, we can follow these steps: ### Step 1: Identify the given values - Capacitance, \( C = 10 \mu F = 10 \times 10^{-6} F \) - Inductance, \( L = 1 H \) - Frequency, \( f = 50 Hz \) - Given \( \pi^2 = 10 \) ### Step 2: Calculate the angular frequency \( \omega \) The angular frequency \( \omega \) is given by the formula: \[ \omega = 2\pi f \] Substituting the value of \( f \): \[ \omega = 2 \pi \times 50 = 100 \pi \, \text{rad/s} \] ### Step 3: Calculate the inductive reactance \( X_L \) The inductive reactance \( X_L \) is calculated using the formula: \[ X_L = \omega L \] Substituting the values: \[ X_L = 100 \pi \times 1 = 100 \pi \, \Omega \] ### Step 4: Calculate the capacitive reactance \( X_C \) The capacitive reactance \( X_C \) is calculated using the formula: \[ X_C = \frac{1}{\omega C} \] Substituting the values: \[ X_C = \frac{1}{100 \pi \times 10 \times 10^{-6}} = \frac{1}{10^{-4} \pi} = \frac{10^4}{\pi} = \frac{10000}{\pi} \, \Omega \] ### Step 5: Calculate the impedance \( Z \) Since there is no resistance in the circuit, the impedance \( Z \) is given by: \[ Z = \sqrt{R^2 + (X_L - X_C)^2} \] Since \( R = 0 \): \[ Z = |X_L - X_C| \] Substituting the values: \[ Z = |100 \pi - \frac{10000}{\pi}| \] ### Step 6: Simplify the expression To simplify, we find a common denominator: \[ Z = \left| \frac{100 \pi^2 - 10000}{\pi} \right| \] Substituting \( \pi^2 = 10 \): \[ Z = \left| \frac{100 \times 10 - 10000}{\pi} \right| = \left| \frac{1000 - 10000}{\pi} \right| = \left| \frac{-9000}{\pi} \right| = \frac{9000}{\pi} \, \Omega \] ### Step 7: Final Calculation Using \( \pi \approx 3.16 \): \[ Z \approx \frac{9000}{3.16} \approx 2847.5 \, \Omega \] ### Conclusion The impedance of the combination is approximately \( 2847.5 \, \Omega \).

To find the impedance of a series combination of a capacitor and an inductor connected to an AC source, we can follow these steps: ### Step 1: Identify the given values - Capacitance, \( C = 10 \mu F = 10 \times 10^{-6} F \) - Inductance, \( L = 1 H \) - Frequency, \( f = 50 Hz \) - Given \( \pi^2 = 10 \) ...
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