The voltage time (V-t) graoh for triangular wave having peak value `(V_0)` is as shown in fig.

Options

A. `(V_(0))/(sqrt(3))`
B. `(V_(0))/(2)`
C. `(V_(0))/(sqrt(2))`
D. `2 V_(0)`

Answer

1

Explanation

`V = (V_(0) t)/(T//4) = (4 V_(0)t)/(T)`
`V_("rms") = sqrt( (:V^(2):) ) = (4 V_(0))/(T) {(underset(0)overset(T//4)(int)t^(2)dt)/(underset(0)overset(T//4)(int)dt)}= (V_(0))/(sqrt(3))`