In the given circuit assuming inductor and source to be ideal, the phase differece between current `I_(1)` and `I_(2)` :

Options

A. `tan^(-1) ((X_(C ))/(R )) - (pi)/(2)`
B. `tan^(-1) ((X_(C ))/(R ))`
C. `tan^(-1) ((X_(C ))/(R )) + (pi)/(2)`
D. `(pi)/(2)`

Answer

C

Explanation

Let : `V_(s) = V_(s) sin omega t`
`I_(1) = I_(0) sin (omega t - pi//2) , I_(2) = I_(02) sin (omega t + theta)`
`tan theta = (X_(C ))/(R )`
So phase difference `= theta + (pi)/(2) , tan^(-1) ((X_(c ))/(R )) + (pi)/(2)`