For the `AC` circuit shown, the reading of ammeter and voltmeter are `5A` and `50 sqrt(5)` volts respectively, then

Options

A. average power deliverd by the source is `250 W`
B. rms value of `AC` source is 50 volts
C. voltage gain is 2
D. frequency of ac source is 1000rad/s

Answer

A,B,C,D

Explanation

`i_("rms") = 5A`
Reading of voltmeter `= i_("rms") sqrt(R^(2) + X_(C )^(2))`
From this `X_(C ) = 20 Omega implies omega = 10^(3) "rad"//s`
`:. X_(L) = omega L = 20 Omega`
Therefore the circuit is in resonance
`E_("rms") - i_("rms") R = 50 V` also power factor = 1
Av, power `= E_("rms") i_("rms") cos phi = 250 W`
voltage gain ` = (X_(L))/(R ) = 2`