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One application of L-R-C series circuit ...

One application of `L-R-C` series circuit is in high pass or low pass filter, which out either the low or high frequency components of a signal. A has pass filter is shown in figure where the output voltage is taken across the `L-R` where `L-R` combination represents and inductive coil that also has resistance due to the large length of the wire in the coil.

which of the following statementds is correct when `omega` is samll in the case of `V_("out")//V_(s)`

A

`omega RC`

B

`(omega R)/(L)`

C

`omega R L`

D

`(omega R)/(C )`

Text Solution

Verified by Experts

The correct Answer is:
A
As `omega to 0`, `(V_("out"))/(V_(s)) = omega C R`
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One application of L-R-C series circuit is in high pass or low pass filter, which out either the low or high frequency components of a signal. A has pass filter is shown in figure where the output voltage is taken across the L-R where L-R combination represents and inductive coil that also has resistance due to the large length of the wire in the coil. Which statement is correct in the limit of large frequency is reached? (for V_("out")//V_(s))

One application of L-R-C series circuit is in high pass or low pass filter, which out either the low or high frequency components of a signal. A has pass filter is shown in figure where the output voltage is taken across the L-R where L-R combination represents and inductive coil that also has resistance due to the large length of the wire in the coil. Find the ratio V_("out") //V_(s) as a function of the angular frequency omega of the source

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