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A series R-L-C circuit has R = 100 Ohm. ...

A series `R-L-C` circuit has `R = 100 Ohm. L = 0.2 mH` and `C = (1)/(2) mu F`. The applied voltage `V = 20 sin omega t`.
When the current lags the applied voltage by `45^(@)`, the equation of the current is

A

`0.2 sin (omega t + tan^(-1) 0.3)`

B

`0.2 sin (omega t - tan^(-1) 0.3)`

C

`0.3 sin (omega t + tan^(-1) 0.3)`

D

`0.3 sin (omega t - tan^(-1) 0.3)`

Text Solution

Verified by Experts

The correct Answer is:
B
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