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In the given arrangement the square loop...

In the given arrangement the square loop of area `10 cm^(2)` rotates with an angular velocitys `omega` about its diagonal. The loop is connected to a inductance of `L = 100 mH` and a capacitance of `10 mF` in series. The lead wires have a net resistance of `10 Omega`. Given that `B = 0.1 T` and `omega = 63 "rad"//s`

If the current is in phase with voltage, what shouldl be the frequency of rotation of the coil.

A

`31.6 "rad"//s`

B

`29.5 "rad"//s`

C

`25.6 "rad"//s`

D

`20.5 "rad"//s`

Text Solution

Verified by Experts

The correct Answer is:
A

`omega = (1)/(sqrt(LC)) = (1)/(sqrt((0.1)(0.01))) = 31.6 "rad"//s`
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