In the circuit shown in figure :
`R = 10 Omega , L = (sqrt(3))/(10) H, R_(2) = 20 Omega` and `C = (sqrt(3))/(2) mF`. Current in `L - R_(1)` circuit is `I_(1)` in `C - R_(1)` circuit is `I_(2)` and the main current is `I`

At some instant `I_(1)` in the circuit is `10 sqrt(2) A`, then at this instant current `I` will be

Options

A. `20 A`
B. `10 sqrt(2) A`
C. `20 sqrt(2) A`
D. `25 A`

Answer

B

Explanation

At any time total current `i = i_(1) + i_(2)`