Two resistors are connected in series across `5V` rms source of alternating potentail. The potential difference across `6 Omega` resistor is `3 V_(m)`. If `R` is replaced by a pure inductor `L` of such magnitude that current remains same, then the potential difference across `L` is

Answer

4

Explanation

Initially `i=(2)/(R )=(3)/(6) therefore R=4Omega , i=(1)/(2)A`
Whebn `R` is replaced by `L,i` does not change
`therefore (1)/(2)=(5)/(sqrt(4^(2)+X_(L)^(2)))," " therefore X_(L)=8Omega`
`therefore V_(L)=iX_(L)=(1)/(2)xx8=4V`