An ideal choke takes a current fo `10 A` when connected to an ac supply of `125 V` and `50 Hz`. A pure resistor under the same conditions take a current of `12.5 A`. If the two are connected to an ac supply of `100 V` and `40 Hz`, then the current in series combination of above resistor and inductor is `(10^(x))/(sqrt(2))` what is the value of `x`

Answer

1

Explanation

`2pixx50L=(125)/(10) , therefore L=(12.5)/(100pi)` and `R=(125)/(12.5)=10Omega`
In the series combination of `L` and `R`
`i=(100)/(sqrt(R^(2)+(2pixx40L)^(2)))=(100)/(sqrt(10^(2)+10^(2)))=(10)/(sqrt2)`