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(14 x)/(x+1)<(9x-30)/(x-4)...

`(14 x)/(x+1)<(9x-30)/(x-4)`

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(14x)/(x+1)-(8x-30)/(x-4)<0

{ x in R:(14x)/(x+1)-(9x-30)/(x-4)lt0} is equal to

{x in R: (14x)/(x+1)- (9x-30)/(x-4) lt 0} =

(2x-1)/(7)=(14-x)/(14)+7

If x^(3)=(1)/(x^(3))=14, then x-(1)/(x)=5 (b) 4(d)3(d)2

Find x from the following equation using properties of proportion: (x^2-x+1)/(x^2+x+1)=(14(x-1))/(13(x+1))

Resolve (6x^(2)-14x+6)/(x(x-1)(x-2)) into partical fractions.

Solve : (3x +4)/(7) - (x +5)/(14) = (x)/(28) + (x +1)/(14) The following steps are involved in solving the above problem. Arrange them in sequential order (A) 5x + 3 = (3x + 2)/(2) rArr 10 x + 6 = 3x + 2 (B) rArr 7x = -4 (C) Given (3x + 4)/(7) - (x + 5)/(14) = (x)/(28) + (x +1)/(14) rArr (6x + 8 -x -5)/(14) = (x + 2x + 2)/(28) (D) rArr x = -(4)/(7)