" 3."(x-2y+3)(x^(2)+4y^(2)+2xy+6y-3x+9)

Find the product. (x-2y+3)(x^2+4y^2+2xy+6y-3x+9)

Find the following expressions (x-2y+3)(x^2+4y^2+2xy-3x-6y+9)

Simplify : (x- 2y + 3z ) ( x^(2) + 4y^(2) + 9z^(2) + 2xy + 6yz - 3xz)

Find the product of 3x, -4xy, 3x^(2), 4y^(2), 6x^(3)y^(2)

12xy (9x ^ (2) -16y ^ (2)) -: 4xy (3x + 4y)

The following are the steps involved in factorizing 64 x^(6) -y^(6) . Arrange them in sequential order (A) {(2x)^(3) + y^(3)} {(2x)^(3) - y^(3)} (B) (8x^(3))^(2) - (y^(3))^(2) (C) (8x^(3) + y^(3)) (8x^(3) -y^(3)) (D) (2x + y) (4x^(2) -2xy + y^(2)) (2x - y) (4x^(2) + 2xy + y^(2))

Subtract: (i) 5a + 7b - 2c from 3a - 7b + 4c (ii) a - 2b - 3c from -2a + 5b - 4c (iii) 5x^(2) - 3xy + y^(2) from 7x^(2) - 2xy - 4y^(2) (iv) 6x^(3) - 7x^(2) + 5x - 3 from 4 - 5x + 6x^(2) - 8x^(3) (v) x^(3) + 2x^(2) y + 6xy^(2) - y^(3) from y^(3) - 3xy^(2) - 4x^(2) (vi) -11 x^(2) y^(2) + 7xy - 6 from 9x^(2) y^(2) - 6xy + 9 (vii) -2a + b + 6d from 5a - 2b - 3c

Add: 8x^(2) - 5xy - 3y^(2), 2xy - 6y^(2) + 3x^(2) and y^(2) + xy - 6x^(2)