A linearly polarised electromagnetic wave given as `E=E_(0)haticos(kz-omegat)` is incident normally on a perfectly reflecting wall `z=a`. Assuming that the material of the optically inactive, the reflected wave will be give as

A linearly polarized electromagnetic wave given by vecE=E_0 haticos (kz-omegat) is incident normally on a perfectly reflecting infinite wall at z = a. Assuming that the material of the wall is optically inactive, the reflected wave will be given as

A linearly polarized electromagnetic wave given as vec(E )=E_(0)cos(kz-omega t)hat(i) is incident normally on a perfectly reflecting infinite wall at z = a. Assuming that the material of the wall is optically inactive, the reflected wave will be given as

A linearly polarized electromagnetic wave in vacuum is E=3.1cos[(1.8)z-(5.4xx10^(6))t]hat(i)" N/C" is incident normally on a perfectly reflecting wall at z = a. Choose the correct option

The electric field of a plane electromagnetic wave is given by vecE=E_(0)(hatx+haty)sin(kz-omegat) Its magnetic field will be given by :

The electric field of a plane electromagnetic wave is given by vecE=E_(0)(hatx+haty)sin(kz-omegat) Its magnetic field will be given by :

The average energy-density of electromagnetic wave given by E=(50N//C) sin (omegat-kx) will be nearly:

The electric field of a plane electromagnetic wave is given by vec(E)=E_0haticos(kz)cos(omegat) The corresponding magnetic field vec(B) is then given by :