[" 2."x-y=3],[quad (x)/(3)+(y)/(2)=6]

x-y=3,(x)/(3)+(y)/(2)=6

Solve for x and y : (x, y ne 0) (10)/(2x+y)+(3)/(2x-y)=3, (15)/(2x+y)+(9)/(2x-y)=6

Solve for x and y : ( 3x )/( 2) - ( 5y )/( 3) = - 2, ( x)/(3) + ( y)/(2) = (13)/(6)

Find the values of x&y when (2x)/(3)+(y)/(2)=3 and (x)/(2)-(2y)/(3)=(1)/(6)

Solve for x and y (2)/(x)+(2)/(3y)=(1)/(6),(3)/(x)+(2)/(y)=0

if (x-y)^3=216 and (x-y)^5=32 , then find x^3-y^3 . The following steps are involved in solving the above problem. Arrange them in sequential order. (A) Therefore, x-y=6 and x+y=2 . (B) Solving x-y=6 and x+y=2rArrx=4, y=-2 . (C) x^3-y^3=64-(-2)^3=64+8=72 (D) (x-y)^3=216rArr(x-y)^3=6^3rArr x-y=6 and (x+y)^5=32rArr (x+y)^5=2^5rArr x+y=2 .

Find each of the following products: (i) (x - 4)(x - 4) (ii) (2x - 3y)(2x - 3y) (iii) ((3)/(4) x - (5)/(6) y) ((3)/(4)x - (5)/(6) y) (iv) (x - (3)/(x)) (x - (3)/(x)) (v) ((1)/(3) x^(2) - 9) ((1)/(3) x^(2) - 9) (vi) ((1)/(2) y^(2) - (1)/(3) y) ((1)/(2) y^(2) - (1)/(3) y)

2x+5y=8/3, 3x-2y=5/6

6/(x+y)=7/(x-y)+3 , 1/(2(x+y))=1/(3(x-y))

Solve for x and y 2/(3x+2y)+3/(3x-2y)=17/5,5/(3x+2y)+1/(3x+2y)=6/5