=1" and "(x^(2))/(l^(2))-(y^(2))/(m^(2))=1" cut each other orthogonally then "

If the curves (x^(2))/(l^(2))+(y^(2))/(m^(2))=1 and (x^(2))/(64)+(y^(2))/(25)=1 cut each other orthogonally then l^(2)-m^(2)

If the curves x^2/a^2+y^2/b^2=1 and x^2/l^2-y^2/m^2=1 cut each other orthagonally, then

If the curves ax^(2) + by^(2) =1 and a_(1) x^(2) + b_(1) y^(2) = 1 intersect each other orthogonally then show that (1)/(a) - (1)/(b) = (1)/(a_(1)) - (1)/(b_(1))

The curves 2x^(2) + 3y^(2) = 1 and cx^(2) + 4y^(2) = 1 cut each other orthogonally then the value of c is:

If x^(2) + y^(2) - 2x + 3y + k = 0 " and " x^(2) + y^(2) + 8x - 6y = 7 = 0 cut each other orthogonally , the value of k must be

The curve x^(2)-y^(2)=5 and (x^(2))/(18)+(y^(2))/(8)=1 cut each other at any common point at an angle-

If the curve ax^(2) + 3y^(2) = 1 and 2x^2 + 6y^2 = 1 cut each other orthogonally then the value of 2a :

For the circles x^(2) + y^(2) - 2x + 3y + k = 0 and x^(2) + y^(2) + 8x - 6y - 7 = 0 to cut each other orthogonally the value of k must be