lim_(x rarr alpha)[(x sin alpha-alpha sin x)/(x-alpha)]

lim_(x rarr oo)(sin alpha-alpha sin x)/(x-alpha)

sin3 alpha=4sin alpha sin(x+alpha)sin(x-alpha)

sin 3 alpha = 4 sin alpha sin(x + alpha) sin(x-alpha)

lim_(x rarr0)(sin(alpha+x)-sin(alpha-x))/(cos(alpha+x)-cos(alpha-x))

The value of lim_(x rarr0)(sin alpha x-sin beta x)/(e^(alpha x)-e^(beta x))

The value of lim_(x rarr0)(sin alpha x+sin beta x)/(e^(alpha x)-e^(beta x)) equals

lim_(x rarr2)((cos alpha)^(x)+(sin alpha)^(x)-1)/(x-2)

Prove that lim_(x rarr4)((cos alpha)^(x)-(sin alpha)^(x)-cos2 alpha)/(x-4)=cos^(4)alpha ln(cos alpha)-sin^(4)alpha,alpha in(0,(pi)/(2))

sin3alpha = 4 sin alpha sin(x+alpha)sin(x-alpha)