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In the formation of HBr form H(2) and Br...

In the formation of `HBr` form `H_(2)` and `Br_(2)`, following mechanism is observed:
I. `Br_(2) hArr 2Br^(*)` (Equilibrium step)
(II) `H_(2) + Br^(*)rarr HBr+H^(*)` (Slow step)
(III) `H^(*) + Br_(2) rarr HBr + H^(*)` (Fast step)
The rate law for the above reaction is

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