If an alternating voltage is represented as
`E=141 sin (628 t)`, then the rms value of the voltage and the frequency are respectively

If an alternating voltage is represented as E = 141 sin (628t), then the rms value of the voltage and the frequency are respectively.

If an alternating voltage is represented as v = 300 sin 600 t then the arms value of the voltage and the frequency are respectively :

If an alternating voltage is represented as v = 300 sin 600 t then the arms value of the voltage and the frequency are respectively :

If an alternating voltage is represented as E = 141 sin (628t) , then (1) the rms voltage is 141V (2) the rms voltage is 100V (3) the frequency is 50 Hz (4) the frequency is 100 Hz

An alternating voltage is represented as E=20 sin 300 t . The average value of voltage over one cycle will be

An alternating voltage is represented by V = 240 sin 100 πt V. Find the peak voltage, rms voltage, frequency of the source.

The equation of an alternating voltage is V =100sqrt2 sin 100pit volt. The RMS value of voltage and frequency will be respectively

An AC voltage is given as e=e_(1) sin omega t . Find the RMS value of this voltage.

A alternating voltage varies with time (t) as V=100sin(50pit) . The rms voltage and the frequency respectively, are

The instantaneous value of alterninig voltage is given by E = 140 sin 300 t. what is rms value of voltage and frequency of supply ? Take pi = 3 and sqrt2 = 1.4 .