A parallel plate capacitor having plate area `A` and separation `4d` is connected to a battery of emf `V_(0)`. A diellectric slab of thickness `2d` and dielectric constant `2.0` is inserted into the gap. (a) find the increase in energy strored in capacitor. (b) Now battery is removed and dielectric slab taken out, find further increase in energy.

A parallel -plate capacitor having plate area 400 cm ^2 and separation between the plate 1.0mm is connected to a power supply of 100V. A dielectric slab of thickness1.0mm and dielectric constant 5.0 is inserted into the gap .(a)Find the increase in electrostatic energy .(b) If the power supply is now disconnected and the dielectric slab is taken out , find the further increase in energy. (c) Why does the energy increase in inserting the slab as well as in taking it out?

A parallel -plate capacitor having plate area 400 cm ^2 and separation between the plate 1.0mm is connected to a power supply of 100V. A dielectric slab of thickness1.0mm and dielectric constant 5.0 is inserted into the gap .(a)Find the increase in electrostatic energy .(b) If the power supply is now disconnected and the dielectric slab is taken out , find the further increase in energy. (c) Why does the energy increase in inserting the slab as well as in taking it out?

A palller -plate capacitor having plate area 400 cm ^2 and separation between the plate 1.0mm is connecred to a power supply of 100V. A diestric slab of thickness1.0mm and diestric constant 5.0 is inserted into the gap .(a)Find the increase in electrostatic energy .(b) If the power supply is now disconnected and the dielectric slab is taken out , find the further increase in energy. (c) Why does the energy increase in inserting the slab as well as in taking it out?

A parallel plate capacitor (plate length L , plate width b , separation between plates d) is connected to a battery of emf V . A dielectric slab of dielectric constant K and before capacitor. Determine the force by which dielectric is attrached by capacitor.

A parallel plate capacitor has plate of length 'l' width 'w' and separation of plates is 'd' . It is connected to a battery of emf V . A dielectric slab of the same thickness 'd' and of dielectric constant k=4 is being inserted between the plates of the capacitor . At what lenght of the slab inside plates , will the energy stored in the capacitor be two time the initial energy stored ?

A parallel plate capacitor has plate of length 'l' width 'w' and separation of plates is 'd' . It is connected to a battery of emf V . A dielectric slab of the same thickness 'd' and of dielectric constant k=4 is being inserted between the plates of the capacitor . At what lenght of the slab inside plates , will the energy stored in the capacitor be two time the initial energy stored ?

Shown a parallel plate capacitor with plates of width b and length l . The separation between the platesis d. The plates are rigidly clamped and connected to a battery of emf V. A dielectric slab of thickness d and dielectric constant K is slowly inserted between the plates. (a) Calculate the energy of the system when a length x of the slab is introduced into the capacitor. (b) what force should be applied on teh slab to ensure that is goes slowly into the capacitor? Neglect any effect of friction or gravity.