Home
Class 12
MATHS
Equation of the tangent to the curve y=e...

Equation of the tangent to the curve y=`e^(-abs(x))` at the point where it cuts the line x=1-

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of the tangent to the curve y=e^(-|x|) at the point where the curve cuts the line x = 1, is

The equation of the tangent to the curve y=e^(-|x|) at the point where the curve cuts the line x = 1, is

Find the equation of the tangent to the curve y = (x-7)/((x-2)(x-3)) at the point where it cuts the x-axis.

Find the equation of the tangent to the curve y=(x-7)/((x-2)(x-3)) at the point where it cuts the x-axis.

Find the equation of the tangent to the curve y=(x-7)/((x-2)-(x-3)) at the point where it cuts the x-axis.

Find the equation of the tangent to the curve y=(x-7)/((x-2)-(x-3)) at the point where it cuts the x-axis.

Find the equation of the tangent to the curve y=(x-7)/((x-2)(x-3)) at the point where it cuts the x-axis.

Find the equation of the tangent to the curve y=(x-7)/((x-2)(x-3) at the point where it cuts the x-axis.

Find the equation of the tangent to the curve y=(x-7)/((x-2(x-3)) at the point where it cuts the x-axis.

Find the equation of the tangent to the curve y=(x-7)/((x-2)(x-3)) at the point where it cuts the x -axis.