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Initially, 0.8 mole of PCl(5) and 0.2 mo...

Initially, 0.8 mole of `PCl_(5)` and 0.2 mol of `PCl_(30` are mixed in one litre vessel. At equilibrium, 0.4 mol of `PCl_(3)` is present. The value of `K_(c )` for the reaction
`PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g)`
would be

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Initially, 0.8 mole of PCl_(5) and 0.2 mol of PCl_(3 are mixed in one litre vessel. At equilibrium, 0.4 mol of PCl_(3) is present. The value of K_(c ) for the reaction PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g) would be

Initially 0.8 mole of PCl_(5) and 0.2 mole of PCl_(3) are mixed in one litre vessel . At equilibrium 0.4 mole of PCl_(3) is present . The value of K_(C) for the reaction PCl_(5(g)) hArr PCl_(3(g)) + Cl_(2(g)) is

For the reaction, PCl_(5)(g)to PCl_(3)(g)+Cl_(2)(g)

1 mole of PCl_(5) taken at 5 atm, dissociates into PCl_(3) and Cl_(2) to the extent of 50% PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) Thus K_(p) is :

1 mole of PCl_(5) taken at 5 atm, dissociates into PCl_(3) and Cl_(2) to the extent of 50% PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) Thus K_(p) is :