`lim_(x->0)((seca x-secb x)/(x^2))`

lim_(x rarr0)(sec x-1)/(x^(2))

lim_(x rarr0)(cos3x-cos x)/(x^(2))cos3x-cos x lim x?0

lim_(x->0)(sin^2x)/x

lim_(x rarr0)(1-cos x^(@))/(x^(2))

a=lim_(x rarr0)(ln(cos2x))/(3x^(2)),b=lim_(x rarr0)(sin^(2)2x)/(x(1-e^(x))),c=lim_(x rarr1)(sqrt(x)-x)/(ln x)

if l=lim_(x->0) (x(1+acosx) - bsinx)/x^3 = lim_(x->0) (1+acosx)/x^2-lim_(x->0) (b sinx)/x^3 where l in R , then

if l=lim_(x->0) (x(1+acosx) - bsinx)/x^3 = lim_(x->0) (1+acosx)/x^2-lim_(x->0) (b sinx)/x^3 where l in R , then

lim_(x rarr 0) (1- cos x)/(x^(2)) is :

lim_(x rarr0)(1-cos x)/(x^(2))

Lim_(x to 0) ( tan x - sin x)/x^(2) is equal to