(p)/(x-q)+(q)/(x-p)=2;x!=p,q

Find (x+2p)/(x-2p) +(x+2q)/(x-2q),"when x" = (4pq)/(p+q) .

In the equation (x-p)/(q)+(x-q)/(p)=(q)/(x-p)+(p)/(x-q),x is not equal to

If x=(p+q)/(p-q) and y=(p-q)/(p+q) then the value of (x-y)/(x+y) is

If the equation x^(2)+px+q=0 and x^(2)+p'x+q'=0 have a common root show that it must be equal to (pq'-p'q)/(q-q') or (q-q')/(p'-p)

Solve for x and y:(q)/(p)x+(p)/(q)y=p^(2)+q^(2);x+y=2pq

If |x| lt 1 then (d)/(dx ) [1+ (px)/(q) + (p (p+q))/(2 !)((x)/(q))^(2) + (p(p+q) (p+ 2q))/(3!) ((x )/(q))+...]=

The lines (p-q)x+(q-r)y+(r-p)=0(q-r)x+(r-p)y+(p-q)=0,(x-p)x+(p-q)y+(q-r)=

If the equation x^2+px+q=0 and x^2+p'x+q'=0 have a common root , prove that , it is either (pq'-p'q)/(q'-q) or, (q'-q)/(p'-p) .

If the equation x^2 + px + q =0 and x^2 + p' x + q' =0 have common roots, show that it must be equal to (pq' - p'q)/(q-q') or (q-q')/(p'-p) .