The line `vecr= veca + lambda vecb` will not meet the plane
`vecr cdot n =q,` if

The line vecr= veca + lambda vecb will not meet the plane vecr cdot vecn =q, if a. vecb.vecn=0,veca.vecn=q b. vecb.vecn" "ne0,veca.vecn" "ne q c. vecb.vecn=0,veca.vecn" "ne q d. vecb.vecn" "ne0,veca.vecn" "ne q

The line vec r = veca+lambda vec b will not meet the plane vecr. vecn= vecq , if___

The equation of the plane containing the line vecr= veca + k vecb and perpendicular to the plane vecr . vecn =q is :

The equation of the plane containing the line vecr= veca + k vecb and perpendicular to the plane vecr . vecn =q is :

A straight line vecr=veca+lambda vecb meets the plane vecr. vec n=0 at p. Then position vector of P is

State the condition for which the line vecr=veca+lambda vecb is parallel to the plane vecr. vecn=d . Prove that the line vecr=(hati+ hatj)+ lambda (2 hati+ hat j+4 hatk) is parallel to the plane vec r.(-2 hati+ hatk)=5 . Also , find the distance between the line and the plane.

A straighat line vecr=veca+lamdavecb meets the plane vecr.vecn=p in the point whose position vector is (A) veca+((veca.hatn)/(vecb.hatn))vecb (B) veca+((p-veca.hatn)/(vecb.hatn))vecb (C) veca-((veca.hatn)/(vecb.hatn))vecb (D) none of these

A straighat line vecr=veca+lamdavecb meets the plane vecr.vecn=p in the point whose position vector is (A) veca+((veca.hatn)/(vecb.hatn))vecb (B) veca+((p-veca.hatn)/(vecb.hatn))vecb (C) veca-((veca.hatn)/(vecb.hatn))vecb (D) none of these

The angle theta the line vecr=vecr+lamdavecb and the plane vecr.hatn=d is given by (A) sin^-1((vecb.hatn)/(|vecb|)) (B) cos^-1((vecb.hatn)/(|vecb|)) (C) sin^-1((veca.hatn)/(|veca|)) (D) cos^-1((veca.hatn)/(|veca|))