`f:R->R, f(x)=x^3+3x+2` and `g:R->R` such that `f(g(x))=x`. Then value of `int_2^6 g(x)dx` is

If f : R rarr R, f(x) = x^(2) + 2x - 3 and g : R rarr R, g(x) = 3x - 4 then the value of fog (x) is

If f : R rarr R, f(x) = x^(2) + 2x - 3 and g : R rarr R, g(x) = 3x - 4 then the value of fog (x) is

If f:R to R, f(x) =x^(2)+2x -3 and g:R to R, g(x) =3x-4 then the value of fog(x) is :

If f :R ->R , f(x)=x^3 +3 ,and g:R->R , g(x)=2x + 1 , then f^(-1)(g^(-1)(23)) equals

If f :R ->R , f(x)=x^3 +3 ,and g:R->R , g(x)=2x + 1 , then f^(-1)(g^(-1)(23)) equals

If f :R ->R , f(x)=x^3 +3 ,and g:R->R , g(x)=2x + 1 , then f^(-1)g^(-1)(23) equals

If f:R->R and g:R-> R are two mappings such that f(x) = 2x and g(x)=x^2+ 2 then find fog and gog .

If f:R rarr R,f(x)=2x-1 and g:R rarr R,g(x)=x^(2) then (gof)(x) equals

Let R be the set of real numbers and the functions f:R rarr R and g:R rarr R be defined by f(x)=x^(2)+2x-3 and g(x)=x+1 Then the value of x for which f(g(x))=g(f(x)) is

If the function f:R rarr R be defined by f(x)=2x-3 and g:R rarr R by g(x)=x^(3)+5 then find the value of (fog)^(-1)(x)