The equation of the tangent tothe curve `y={x^2 sin(1/x),x!=0 and 0, x=0` at the origin is

Similar Questions

Explore conceptually related problems

Find the equation of the tangent to the c u r v ey={x^2sin1/x ,x!=0 0,x=0 at the origin

The equation of the tangent to the curve y={(x^2sin"1/x,xne0),(0,x=0):} at the origin is

Find the equation of the tangent to the curve y={[x^(2)sin(1)/(x),x!=0 at the origin 0,x=0

The equation of the tangent to the curve y = e^(2x) at (0,1) is

Equation of the tangent to the curve y=e^(x) at (0,1) is

Equation of the tangent to the curve y= log x at (1,0) is

The equation of the tangent to the curve y=(1+x)^(y)+sin^(-1)(sin^(2)x) at x=0 is

Find the equation of the tangent to the curve y = 2x^(2) + 3 sin x at x = 0.

The equation of the tangents at the origin to the curve y^2=x^2(1+x) are