30quad 1449^(2)-289b^(2)

Factorize each of the following expressions: 16x^(2)-25y^(2) (2) 27x^(2)-12y^(2)144a^(2)-289b^(2) (4) 12m^(2)-27125x^(2)-45y^(2)(6)144a^(2)-169b^(2)

Factorize each of the following expressions: 16 x^2-25 y^2 (2) 27 x^2-12 y^2 (3) 144 a^2-289 b^2 (4) 12 m^2-27

Usting the identity (a+ b)^(2) = (a^(2) + 2ab +b^(2)), evaluate: (609)^(2) (725)^(2) (491)^(2) (289)^(2)

The product of two natural number is 17 Then,the sum of the reciprocal is of their square is (1)/(289) b.(289)/(290) c.(290)/(289) d.289

Factorize 30 a^(2)b + 40 ab^(2)

Use of the formula (a+b) (a-b) = a^(2) - b^(2) to find the value of : (ii) 30.8 xx 29.2

The value of {(23+2^(2))^((2)/(3))+(140-29)^((1)/(2))}^(2)}^(2) is 196(b)289(c)324(d)400]}

The value of {(23+2^2)^(2/3)+\ (140-19)^(1/2)}^2 , is (a) 196 (b) 289 (c) 324 (d) 400