First three nearest neighboure distance for primitive cubic lattice are respectively (edge length of unit cell = a):

First three nearest neighbour distance for body centred cubic lattice are respectively:

First three nearest neighbour distance for body centered cubic lattice are

First three nearestneighbour distances for body centered cubic lattice are respectively :

First three nearestneighbour distances for body centered cubic lattice are respectively :

First three nearestneighbour distances for body centered cubic lattice are respectively :

First three nearest neighbout distance for body centrered cubic lattice are

First three nearest neighbour distance for primitive cubic unit cell will be (edge length of unit cell = a)

The distance between the nearest neighbours of a body-centred cubic unit cell is equal to 0.866 times the edge length of the unit cell. What is the relation between the edge length and the radius of the constituent particle of this unit cell?

An element crystallises in a face-centred cubic lattice. The distance between the nearest neighbours in the unit cell is 282.8pm. Calculate the edge length of the unit cell, and the radius of an atom of the element.