Recommended Questions
- sin3A+sin2A-sin A=4sin A cos(A)/(2)cos(3A)/(2)
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- sin3A+sin2A-sin A=4sin A*cos((A)/(2))*cos((3A)/(2))
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- sin3A+sin2A-sin A is
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- (sin^(2)3A)/(sin^(2)A)-(cos^(2)3A)/(cos^(2)A)=
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- Let a=(pi)/(7) Show that sin^(2)3a+sin^(2)a=sin2a sin3a
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- Prove that sinA+sin2A+sin4A+sin5A=4 (cosA/2)(cos3A/2)sin3A
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- (sin^(2)3A)/(sin^(2)A)-(cos^(2)3A)/(cos^(2)A)=
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- (sin^(2)3A)/(sin^2A)-(cos^(2)3A)/(cos^2A)=
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- (sin^(2)3A)/(sin^(2)A)-(cos^(2) 3A)/(cos^(2)A)=
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