` lim_(h to 0) (f(2h+2+h^(2))-f(2))/(f(h-h^(2)+1)-f(1))` given that f'(2) = 6 and f'(1) = 4,

lim_(h rarr 0) (f(2h+2+h^(2))-f(2))/(f(h-h^(2)+1)-f(1)) given that f^(')(2) = 6 , and f^(')(1) =4

lim_(h rarr0)(f(2h+2+h^(2))-f(2))/(f(h-h^(2)+1)-f(1)) given that f'(2)=6 and f'(1)=4 does not exist (a) is equal to -(3)/(2) (b) is equal to (3)/(2)(c) is equal to 3

underset(h to 0)lim (f(2h+2+h^(2))-f(2))/(f(h-h^(2)+1)-f(1))"given that "f'(2)=6and f'(1)=4

lim_(h to 0) (f(2h+2+h^(2)))/(f(h-h^(2)+1)-f(1))"given that "f'(2)=6and f'(1)=4

lim_(h->0) (f(2h+2+h^2)-f(2))/(f(h-h^2+1)-f(1)) given that f'(2)=6 and f'(1)=4 then (a) limit does not exist (b) is equal to - 3/2 (c) is equal to 3/2 (d) is equal to 3

lim_(h->0) (f(2h+2+h^2)-f(2))/(f(h-h^2+1)-f(1)) given that f'(2)=6 and f'(1)=4 then (a) limit does not exist (b) is equal to - 3/2 (c) is equal to 3/2 (d) is equal to 3

lim_(h->0) (f(2h+2+h^2)-f(2))/(f(h-h^2+1)-f(1)) given that f'(2)=6 and f'(1)=4 then (a) limit does not exist (b) is equal to - 3/2 (c) is equal to 3/2 (d) is equal to 3

lim_(h->0) (f(2h+2+h^2)-f(2))/(f(h-h^2+1)-f(1)) given that f'(2)=6 and f'(1)=4 does not exist (a) is equal to - 3/2 (b) is equal to 3/2 (c) is equal to 3