The 4th term of an A.P is equal to the 3 times ofthe first term and 7th term exceeds twice the 3rd term by 1. Find first term and common difference

Explanation

Let the A.P be `a,a+d,a+2d.......` where `a` is the first term and d is the common difference.

Given`a_4=3a_1`=>`a+3d=3a`=>`3d=2a`....(1)

also `a_7=2a_3+1`=>`2d=a+1`...(2)

solving (1) and(2) we get `d=2` and `a=3`