The value of acceleration due to gravity at a place is `9.8ms^(-2)`. Find its value in `km h^(-2)`

Taking the value of the acceleration due toj gravity as 10 m s^(-2) , Find its value in km h^(-2).

Value of acceleration due to gravity is 9.8m//sec^(2) . Find its value in km//hr^(2) .

The value of g (acceleration due to gravity) at earth's surface is 10 ms^(-2) . Its value in ms^(-2) at the centre of the earth which is assumed to be a sphere of radius R metre and uniform mass density is

The value of g (acceleration due to gravity) at earth's surface is 10 ms^(-2) . Its value in ms^(-2) at the centre of the earth which is assumed to be a sphere of radius R metre and uniform mass density is

Suppose the acceleration due to gravity at a place is 10 m/s^2 . Find its value in cm//(min)^2

The value of acceleration due to gravity at Earth's surface is 9.8ms^(-2) . The altitude (in metre) above its surface at which the acceleration due to gravity decreases to 4.9ms^(-2) , is close to :(Radius of earth =6.4xx10^(6)m )

Suppose the acceleration due to gravity at a place is 10 m/s^2 . Find its value in cm//(minute).

Suppose the acceleration due to gravity at a place is 10 m/s^2 . Find its value in cm//(minute).

The acceleration due to gravity is 9.8 m s^(-2) . Give its value in ft s^(-2)