the median AB of `Delta ABC` is bisected at Eand BE is produced to meet the side AC in f.then the ratio `AF:FC=`

The median AD to DeltaABC is bisected at E and BE is produced to meet the side AC in F. Show that bar(AF)=1/3bar(AC)

The median AD of triangle ABC is bisected at F and BF is produced to meet the side AC in P. If AP=lambda AC then what is the value of lambda

The median AD of a triangle ABC is bisected at F, and BF is produced to meet the side AC in P. If AP = lamdaAC , then what is the value of lamda .?

The median AD of the triangle ABC is bisected at E and BE meets AC at F. Find AF:FC.

The median AD of the triangle ABC is bisected at E and BE meets AC at F. Find AF:FC.

The median AD of the triangle ABC is bisected at E and BE meets AC at F. Find AF:FC.

The median AD of the triangle ABC is bisected at E and BE meets AC at F. Find AF:FC.

The median AD of the triangle ABC is bisected at E and BE meets AC at F. Find AF:FC.

The median AD of the triangle ABC is bisected at E and BE meets AC at F. Find AF:FC.