The position vector of A , B are `vec a and vec b ` respectively. The position vector of C is `(5 vec a/3)- vec b`then

If vec(a) and vec(b) are the position vectors of vec(A) and vec(B) respectively, then find the position vector of a point vec(C) and vec(BA) produced such that vec(BC) = 1.5 vec(BA) . Also, it is shown by graphically.

The position vectors of the points A,B,C are vec a, vec b, vec c respectively. If 3 vec a + 2 vec c= 5 vecb , are the points A,B,and C collinear? If so find AB:BC .

If vec(b) and vec(c) are the position vectors of the points B and C respectively, then the position vector of the point D such that vec(BD) = 4 vec(BC) is

If vec(b) and vec(c ) are the position vectors of the points B and C respectively, then the position vector of the point D such that vec(BD)= 4 vec(BC) is

If veca and vecb are position vectors of A and B respectively, then the position vector of a point C in vec(AB) produced such that vec(AC) =2015 vec(AB) is

If veca and vecb are position vectors of A and B respectively, then the position vector of a point C in vec(AB) produced such that vec(AC) =2015 vec(AB) is

If veca and vecb are position vectors of A and B respectively, then the position vector of a point C in vec(AB) produced such that vec(AC) =2015 vec(AB) is

If a and b are position vectors of A and B respectively the position vector of a point C on AB produced such that vec AC=3vec AB is

If a and b are position vectors of A and B respectively the position vector of a point C on AB produced such that vec(AC)=3 vec(AB) is

The position vector of the points A and B are respectively vec(a) and vec(b) . Find the position vectors of the points which divide AB in trisection.