if `h^2=ab` , then the lines represented by `ax^2+2hxy+by^2=0` are

If the slopes of the lines represented by ax^(2)+2hxy+by^(2)=0 are in the ratio m:n then ((m+n)^(2))/(mn)=

If the slope of one of the lines represented by ax^2+2hxy+ by^2 =0 be the square of the other , then (a+b)/h+(8h^2)/(ab) is :

If theta is the angle between the lines represented by ax^(2)+2hxy+by^(2)=0 , then tantheta=

If the slope of one of the lines represented by ax^(2)+2hxy+by^(2)=0 is square of the slope of the other line, then

If the slope of one of the lines represented by ax^2 + 2hxy+by^2=0 be the nth power of the other , prove that , (ab^n)^(1/(n+1)) +(a^nb)^(1/(n+1))+2h=0 .

If the slope of one of the lines represented by ax^2 + 2hxy+by^2=0 be the nth power of the other, prove that , (ab^n)^(1/(n+1)) +(a^nb)^(1/(n+1))+2h=0 .

If the slope of one of the lines represented by ax^2 + 2hxy+by^2=0 be the nth power of the , prove that , (ab^n)^(1/(n+1)) +(a^nb)^(1/(n+1))+2h=0 .

Assertion (A) : The slopes of one line represented by 2x^(2)–5xy+2y^(2) = 0 is 4 times the slope of the second line. Reason (R): If the slopes of lines represented by ax^(2)+2hxy+by^(2)=0 are in m:n then ((m+n)^(2))/(mn)=(4h^(2))/(ab)

If the slope of one of the lines represented by ax^2+2hxy+by^2=0 is the sqaure of the other , then