The number of atoms in `100 g an fcc` crystal with density `d = 10 g//cm^(3)` and the edge equal to 100 pm is equal to

The number of atoms in 100 g of an FCC crystal with density d = 10 g//cm^(3) and cell edge equal to 100 pm, is equal to

The number of atoms in 100 g of a fcc crystal with density d= 10 g/ cm^(-3) and cell edge equal to 200 pm, is equal to ____.

The number of atoms is 100 g of a fcc crystal with density = 10.0 g//cm^(3) and cell edge equal to 200 pm is equal to

The number of atoms in 100 g of an fcc crystal with density = 10.0g cm^(-3) and cell edge equal to 200 pm is equal to

The number of atoms in 100 g of an fcc crystal with density = 10.0g cm^(-3) and cell edge equal to 200 pm is equal to

The number of atoms in 100 g of an fcc crystal with density = 10.0g cm^(-3) and cell edge equal to 200 pm is equal to