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1 g of steam at 100^@C and an equal mass...

1 g of steam at `100^@C` and an equal mass of ice at `0^@C` are mixed. The temperature of the mixture in steady state will be (latent heat of steam`=540 cal//g`, latent heat of ice `=80 cal//g`,specific heat of water `=1 cal//g^@C`)

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