Work done in converting 1 g of ice at `-10^@C` into steam at `100^@C` is

Work done in converting one gram of ice at -10^@C into steam at 100^@C is

What is the amount of work done to convert 40 g of ice at -10^(@)C into steam at 100^(@)C ? Specific heat of ice = 0.5 cal cdot g^(-1) cdot ^(@)C^(-1) , latent heat of fusion of ice =80 cal cdot g^(-1) , latent heat of steam = 540 cal cdot g^(-1), J = 4.2 xx 10^(7) erg cdot cal^(-1) .

Heat required to convert 1 g of ice at 0^(@)C into steam at 100 ^(@)C is

Heat required to convert 1 g of ice at 0^(@)C into steam at 100 ^(@)C is

What is the amount of heat required (in calories) to convert 10 g of ice at -10^(@)C into steam at 100^(@)C ? Given that latent heat of vaporization of water is "540 cal g"^(-1) , latent heat of fusion of ice is "80 cal g"^(-1) , the specific heat capacity of water and ice are "1 cal g"^(-1).^(@)C^(-1) and "0.5 cal g"^(-1).^(@)C^(-1) respectively.