The length of a sonometer wire is `0.75m`, and density `9xx10^(3)m`. It can bear a stress of `8.1xx10^(8)N//m^(2)` without exceeding the elastice limit. What is the fundamental frequency that can be produced in the wire?

The length of a sonometer wire is 0.75m and density 9xx10^3 kgm^(-3) . It can bear astress of 8.1xx10^8 Nm^(-2) without exceeding the elastic limit Calculate the fundamental frequency that can be produced in the wire.

The length of a sonometer wire is 0.75 m and density is 9 xx 10^3 kg/ m^3 . It can bear a stress of 8.1 xx 10^8 N/ m^2 without exceeding the elastic limit. Then the fundamental frequency that can be produced in the wire is

The length of a sonometer wire is 0.75 m and density is 9 xx 10^3 kg/ m^3 . It can bear a stress of 8.1 xx 10^8 N/ m^2 without exceeding the elastic limit. Then the fundamental frequency that can be produced in the wire is

The length of a sonometer wire is 1.25m and density 8xx10^(3)kg//m^(3) . It can bear a stress of 3.2xx10^(8)N//m^(2) without exceeding the elastic limit. The fundamental frequency that can be produced in the wire, is :-

The length of a sonometer wire is 0.75 m and density 9xx 10^(3) Kg//m^(3) . It can bear a stress of 8.1 xx 10^(8) N//m^(2) without exceeding the elastic limit . The fundamental that can be produced in the wire , is

The length of a sonometer wire is 0.75 m and density 9xx 10^(3) Kg//m^(3) . It can bear a stress of 8.1 xx 10^(8) N//m^(2) without exceeding the elastic limit . The fundamental that can be produced in the wire , is

A sonometer wire has a length of 0.75 m and density of the material of the wire is 10^(4) kg//m^(3) . If the wire can bear a stress of 7.5 xx 10^(8) N//m^(2) without exceeding the elastic limit, what fundamental frequency can be produced in the wire ?

On applying a stress of 20 xx 10^(8) N//m^(2) the length of a perfectly elastic wire is doubled. It Young's modulus will be