The capacity of a parallel plate condenser is `10 muF` without dielectric. Dielectric of constant `2` is used to fill half the distance between the plates, the new capacitance in `muF` is

A parallel plate capacitor has a capacitance of 10 mu F without dielectric. A dielectric of dielectric constant 2 is used to fill exactly half the thickness between the plates. The capacitance in mu F, now is

The capacity of a parallel plate air condenser is m mu F .If a dielectric of dielectric constant 8 is introduced between the plates,then its new capacity is 24 mu F . Find the value of m .

The capcity of a parallel plate condenser is 10 muF , when the distance between its plates is 8 cm . If the distance between the plates is reduced to 4 cm , then the capacity of this parallel plate condenser will be

Derive an expression for capacity of a parallel plate condenser filled with dielectric

The capacity of a parallel plate condenser filled with material of dielelctric constant 8 is 16 muF . Its capacity, if the dielectric is removed , will be

The capacity of a parallel plate condenser without any dielectric is C. If the distance between the plates is doubled and the space between the plates is filled with a substance of dielectric constant 3, the capacity of the condenser becomes:

The capacity of a parallel plate condenser without any dielectric is C. If the distance between the plates is doubled and the space between the plates is filled with a substance of dielectric constant 3, the capacity of the condenser becomes:

The capacity of a parallel plate condenser with dielectric constant 10 is 12 mu F . What will be its capacity if dielectric is removed ?

The capacity of a parallel plate condenser with dielectric constant 10 is 16xx10^(-6)F . If the dielectric is removed, then the new capacity will be