For a certain reaction of order 'n' the time for half change `t_(1//2)` is given by : `t_(1//2)=(2-sqrt(2))/KxxC_(0)^(1//2)` where `K` is rate constant and `C_(0)` is the initial concentration. The value of `n` is:

For a certain reaction involving a single reaction, it is found that C_(0)sqrt(t_(1//2)) is constant where C_(0) is the initial concentration of reactant and t_(1//2) is the half-life. The order of reaction is:

For zero order reaction , t_(1//2) will be ( A_0 is the initial concentration , K is rate constant)

For zero order reaction , t_(1//2) will be ( A_0 is the initial concentration , K is rate constant)

For the zero order reaction, A to Products, with rate constant k, half-life period is given by t_(1//2) =………………… .

Given that for a reaction of nth order, the integrated rate equation is: K=1/(t(n-1))[1/C^(n-1)-1/C_(0)^(n-1)] , where C and C_(0) are the concentration of reactant at time t and initially respectively. The t_(3//4) and t_(1//2) are related as t_(3//4) is time required for C to become C_(1//4 ) :