Home
Class 11
CHEMISTRY
The solubility of AgCl in 0.1 M NaCl is ...

The solubility of `AgCl` in `0.1 M NaCl` is (`K_(sp)` of `AgCl = 1.2 xx 10^(-10)`)

Promotional Banner

Similar Questions

Explore conceptually related problems

The solubility of AgCl in 0.1M NaCI is (K_(sp) " of AgCl" = 1.2 xx 10^(-10))

The solubility of AgCl in 0.1M NaCI is (K_(sp) " of AgCl" = 1.2 xx 10^(-10))

What would be the solubility of AgCl in 0.1 M NaCl solution ? (K_(sp)" for AgCl"=1.2xx10^(-10))

Determine the solubility of AgCl in 0.1 M BaCl_2 [K_(sp)" for "AgCl=1 xx 10^(-10)]

The solubility of AgCl in 0.2 M NaCl is [K_(sp) AgCl =1.8 xx 10^(-10)]

The molar solubility of AgCl in 1.8 M AgNO_(3) solution is ( K_(sp) of AgCl = 1.8 xx 10^(-10) )

Solubility of AgCl in 0.1 M CaCl_2 solution will be (K_(sp) of AgCl= 1.8×(10)^(-10) )

Solubility of AgCl in 0.1 M CaCl_2 solution will be ( K_(sp) of AgCl= 1.8×(10)^(-10) )