In Fig, `E =5` volt , `r = 1 Omega, R_(2) = 4 Omega, R_(1) = R_(3) = 1 Omega` and `C = 3 muF`. Then the numbercal value of the charge on each plate of the capacitor is

In the circuit shown , the batteries have emf E_1 = E_2= 1V , E_3 = 2.5 V, and the resistance R_1 = 10Omega, R_2 = 20 Omega , Capacitance C = 10 muF . The charge on the left plate of the charge on the left plate of the capacitor C at steady state is

In the circuit shown , the batteries have emf E_1 = E_2= 1V , E_3 = 2.5 V, and the resistance R_1 = 10Omega, R_2 = 20 Omega , Capacitance C = 10 muF . The charge on the left plate of the charge on the left plate of the capacitor C at steady state is

In the given circuit. E_(1) = 6 volts, E_(2) = 2 volts, E_(3) = 6 volts R_(1) = 6OmegaR_( 2)=2Omega R_(3) = 4Oemga, R_(4) = 3Omega and C=5muF . Find the current in R_(3) and energy stored in the capacitor at steady state

In the circuit shown in fig. R_(1) = 10 Omega, R_(2) = 5 Omega, C_(1) = 1 muF, C_(2) = 2muF, and E =6V. Calculate the charge on each capactor in the stedy state.

In the circuit shown in fig. R_(1) = 10 Omega, R_(2) = Omega, C_(1) = 1 muF, C_(2) = 2muF, and E =6V. Calculate the charge on each capactor in the stedy state.

In the circuit shown in figure, R(1) = 1Omega, R_(2) = 2Omega, C_(1) = 1 muF, C_(2) = 2 muF and E = 6 V . Calculate charge on each capacitor in steady state

In the circuit shown in figure, R(1) = 1Omega, R_(2) = 2Omega, C_(1) = 1 muF, C_(2) = 2 muF and E = 6 V . Calculate charge on each capacitor in steady state

In the circuit given E = 6.0 volt, R_(1) = 100Omega, R_(2) = R_(3)=50Omega and R_(4)=75Omega . The equivalent resistance of the circuit, in ohms is