The length intercepted between the planes `x+y+z=3` and `x+y+z=2` by the line `(x-1)/2=(y+1)/1=(z-3)/-1` is:

The angle between the planes x+y+z=1 and x-2y+3z=1 is

Let the intercept made by the line (x)/(1)=(y)/(2)=(z)/(3) between the plane x+y+z=3 and the line (x-1)/(2)=(y-2)/(-1)=(z-3)/(-1) is lambda then (4 lambda)/(sqrt(14)) is

Find the angle between the planes 3x+y+2z=1 and 2x-y+z+3 = 0 .

Find the angle between the planes 3x+y+2z=1 and 2x-y+z+3 = 0 .

Find the angle between the plane x+y+z-2=0 and line (x+3)/2=(y-1)/1=(z+1)/4

The equation of the plane passing through the line of intersection of the planes x+y+z+3 =0 and 2x-y + 3z +2 =0 and parallel to the line (x)/(1) = (y)/(2) = (z)/(3) is

Find the angle between the line (x+1)/2 = y/3 = (z-3)/6 and the plane 10x+2y-11z = 3

The angle between the lines (x+1)/1 = (y-3)/2 = (z+2)/3 and x/3 = (y-1)/(-2) = z/1 is