In the circuit shown, find the value of resistance R in terms of inductance L and capacitance C such that the current through the cell remains constant forever after the switch is closed.

In the circuit diagram the current through the battery immediately after the switch S is closed is

In the circuit diagram the current through the battery immediately after the switch S is closed is

Consider the circuit shown in figure. The current through the battery a long time after the switch S is closed is:

Consider the circuit shown in figure. The current through the battery a long time after the switch S is closed is:

The circuit shown in the Figure is in steady state. Find the rate of change of current through L immediately after the switch S is closed.

The circuit consists of two resistors (of resistance R_(1) = 20 Omega and R_(2) = 10 Omega ), a capacitor (of capacitance C =10 muF ) and two ideal cells. In the circuit shown the capacitor is in steady state and the switch S is open The current through the resistor R_(2) just after the switch S is closed is :

The circuit consists of two resistors (of resistance R_(1) = 20 Omega and R_(2) = 10 Omega ), a capacitor (of capacitance C =10 muF ) and two ideal cells. In the circuit shown the capacitor is in steady state and the switch S is open The current through the resistor R_(2) just after the switch S is closed is :

in the figure shown , a circuit contains two identical resistors with resistance R= Omega and an inductance with L=2 H ,An ideal battery of 15 V is connected in the circuit what will be the current through the battery long after the switch is clossed ?

in the figure shown , a circuit contains two identical resistors with resistance R= Omega and an inductance with L=2 H ,An ideal battery of 15 V is connected in the circuit what will be the current through the battery long after the switch is clossed ?

In the circuit shown, the cell is deal. The coil has an inductance of 4H and zero resistance. F is a fuse of zero resistance and will blow when the current through it reaches 5 A . The switch is closed at t=0 . The fuse will blow: