Assuming that 200MeV of energy is released per fission of uranium ato, find the number of fission per second required to release one kilowatt power.

Assuming that 200MeV of energy is released per fission of uranium atom, find the number of fission per second required to release one kilowatt power.

(a) Calculate the energy released by the fission of 2g of ._(92)U^(235) in kWh . Given that the energy released per fission is 200MeV . (b) Assuming that 200MeV of enrgy is released per fission of uranium atom, find the number of fissions per second required to released 1 kilowatt power. (c) Find the amount of energy produced in joules due to fission of 1g of ._(92)U^(235) assuming that 0.1% of mass is transformed into enrgy. ._(92)U^(235) = 235 amu , Avogadro number = 6.023 xx 10^(23)

The energy released per fission is

The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to prodice 6.4W power is

The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to prodice 6.4W power is

The energy released by the fission of one uranium atom is 200 MeV. The number of fissions per second required to produce 3.2 MW of power is :

The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to produce 6.4 W power is_____.

The energy released by the fission of one uranium atom is 200 MeV. The number of fissions per second required to produce 3.2 W of power is (Take leV = 1.6xx10^(-19)J)